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济南水稳料:5%水泥稳定级配碎石配合比中的5%是什么意思

来源:http://www.ycgjglcl.com/ 日期:2025-10-22

  5%水泥稳定级配碎石配合比中的5%是什么意思?如何计算?

  What does 5% mean in the mix proportion of 5% cement stabilized graded crushed stone? How to calculate?图10

  答:

  Answer:

  1、5%是水泥的用量。

  1. 5% is the amount of cement used.

  2、是质量比或者说是重量比,决不是体积比。

  2. It's a mass ratio or weight ratio, not a volume ratio.

  3、采用正推方法,即知道5%的前提下,去计算水泥用量,怎么算?

  3. Using the forward calculation method, that is, knowing 5% of the premise, how to calculate the cement dosage?

  水泥:集料=5:100,水泥为集料质量的5%,即:5÷100,这就工程上的百分比,而不是数学上的。即,以集料为100,另外加入5的水泥。

  Cement: Aggregate=5:100, cement is 5% of the aggregate mass, which is 5 ÷ 100. This is a percentage in engineering, not in mathematics. That is, with an aggregate of 100, an additional 5% cement is added.

  例题:某市政道路基层采用18cm+18cm+18cm三层的5%水泥稳定级配碎石,击实试验取得的最大干密度为2262㎏/m?(2.262g/?),含水量6.4%,则每立方米:

  Example: A municipal road base uses 5% cement stabilized graded crushed stone with three layers of 18cm+18cm+18cm. The maximum dry density obtained from the compaction test is 2262 kg/m ? (2.262g/?), with a moisture content of 6.4%. Therefore, per cubic meter:

  水泥用量=2262㎏×5%÷(1+5%)=2262×5÷(100+5)=107.71㎏≈108㎏

  Cement dosage=2262kg × 5% ÷ (1+5%)=2262kg × 5 ÷ (100+5)=107.71kg ≈ 108kg

  集料用量=2262-108=2154㎏

  Aggregate dosage=2262-108=2154kg

  或2262㎏×1÷(1+5%)=2262×100÷(100+5)=2154.29㎏≈2154㎏

  Or 2262 kg × 1 ÷ (1+5%)=2262 × 100 ÷ (100+5)=2154.29 kg ≈ 2154 kg

  用水量=2262㎏×6.4%=144.77㎏≈145㎏

  Water consumption=2262kg × 6.4%=144.77kg ≈ 145kg

  所以,5%水泥稳定级配碎石配合比=水泥:集料:水

  So, the mix ratio of 5% cement stabilized graded crushed stone=cement: aggregate: water

  =108 :2154 :145

  =108 :2154 :145

  ≈5 :100 :6.72

  ≈5 :100 :6.72

  ≈5% :100% :6.72%

  ≈5% :100% :6.72%

  4、请计算一下,如果是数学意义上的5%水稳级配碎石,在工程上是百分之几?

  4. Please calculate, what percentage is 5% water stable graded crushed stone in mathematical terms in engineering?

  水泥:(水泥+集料)=5:(5+95),则

  Cement: (cement+aggregate)=5: (5+95), then

  水泥:集料=5:95=5.26%

  Cement: aggregate=5:95=5.26%

  答案是:5.26%

  The answer is: 5.26%

  所以,工程上的5%若按数学上计算则为4.76%。

  So, if calculated mathematically, the 5% in engineering is 4.76%.

  以上只是用来计算,实际工程中不采用数学意义上的5%~~~

  The above is only for calculation, and the mathematical 5% is not used in actual engineering

  5、再请计算一下,某市政道路施工图纸中对5%水泥稳定级配碎石的图纸说明如下:

  5. Please calculate again. The drawing description for 5% cement stabilized graded crushed stone in a municipal road construction drawing is as follows:

  图片

  image

  这样的水稳,水泥用量是百分之几?

  What percentage of cement is required for this water stability?

  答:这个就是设计单位给的建议,这个就是数学意义上的5%了,工程上水泥用量是多少呢?

  Answer: This is the suggestion given by the design unit, which is 5% in mathematical terms. What is the amount of cement used in engineering?

  5÷95=5.26%

  5÷95=5.26%

  同第4条所述。

  As stated in Article 4.

  所以,这个设计图纸上设计单位给的建议,可以不采纳,是超标的。对现场施工的工程技术人员容易引起误解。

  So, the suggestions given by the design unit on this design drawing can be ignored, as they exceed the standard. Misunderstandings can easily arise among engineering and technical personnel involved in on-site construction.

  6、水泥稳定级配碎石相关的规范、规程

  6. Specifications and regulations related to cement stabilized graded crushed stone

  1)JTG 3432-2024《公路工程集料试验规程》,自2024年5月1日开始实施。《公路工程集料试验规程》(JTG E42—2005)同时废止。

  1) JTG 3432-2024 "Code for Testing of Aggregates in Highway Engineering" will be implemented from May 1, 2024. The "Code for Testing Aggregates in Highway Engineering" (JTG E42-2005) is simultaneously abolished.

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